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6y^2-36y-42=0
a = 6; b = -36; c = -42;
Δ = b2-4ac
Δ = -362-4·6·(-42)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-48}{2*6}=\frac{-12}{12} =-1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+48}{2*6}=\frac{84}{12} =7 $
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